I have several problems I would like to submit and will pay. I have no budget for this, willing to pay (or at least entertain quotes) If interested, I can email specifics and all problems.

Pg. 271 problem 3

Assume that the parallel lines l and l’ have a common perpendicular segment MM’. Prove that MM’ is the shortest segment between any point of l and any point of l’. (hint in showing MM’ < AA’first dispose of the case in which AA’ is perpendicular to l’ by means of a result about Lambert quadrilaterals and then take care of the other case by exercise 22, chapter 4

Exercise 22 chapter 4

Proposition 4.5:

In a triangle ABC, the greater angle lies opposite the greater side and the greater side lies opposite

the greater angle, ie AB>BC if and only if angle C > angle A.

Subject | Mathematics |

Due By (Pacific Time) | 11/06/2012 12:00 am |

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