4 problems I need help with. Just 4.

Find the legnth of the curve bounded by y=2/3(x^2 +1)^3/2 from x=0 to x=3.

Find the latersal surface area of the cone bounded by the segment y=(7/3)x, 0<= x<= 8 about the x-axis./

Solve the initial value problem: ds/dt= 12t(3t^2 -1)^3... s(1)=9.

Fidn the area of the region enclosed by the curves y= x^2 -7 and y=2.

Subject | Mathematics |

Due By (Pacific Time) | 04/09/2014 02:40 pm |

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