A ball is thrown straight upward with an initial velocity of 52 ft/sec. Its height above the ground after seconds is given by the formula h(t) = -16t^2=52t. What is the maximum height that the ball attains before hitting the ground?

A ball is thrown straight upward with an initial velocity of 52 ft/sec. Its height above the ground after seconds is given by the formula

h(t) = -16t^2 + 52t. At what time will the ball hit the ground?

Subject | Mathematics |

Due By (Pacific Time) | 04/26/2013 12:00 am |

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