Project #88173 - physics

In a cyclotron (one type of particle accelerator), a deuteron (of mass 2.00 u) reaches a final speed of 10.7% of the speed of light while moving in a circular path of radius0.425 m. What magnitude of magnetic force is required to maintain the deuteron in a circular path?

 N

 

 

A space station, in the form of a wheel 112 m in diameter, rotates to provide an "artificial gravity" of 2.60 m/s2 for persons who walk around on the inner wall of the outer rim. Find the rate of the wheel's rotation in revolutions per minute that will produce this effect.
 rev/min

 

When a falling meteoroid is at a distance above the Earth's surface of 2.80 times the Earth's radius, what is its acceleration due to the Earth's gravitation?
 m/s2 towards earth

 

Three objects of equal mass (m) are located at three corners of a square of edge length â„“, as shown in the figure below. Find the magnitude and direction of the gravitational field at the fourth corner due to these objects. (Use any variable or symbol stated above along with the following as necessary: G.)

magnitude g = 
 
 
direction  ° (measured counterclockwise from the positive x-axis)

 

 
A light string can support a stationary hanging load of 23.3 kg before breaking. An object of mass m = 2.98kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.784 m, and the other end of the string is held fixed as in the figure below. What range of speeds can the object have before the string breaks?
Part 1 of 4 - Conceptualize
The object will be able to move with any speed between zero and a maximum of several meters per second.
Part 2 of 4 - Categorize
We use the models of a particle under a net force and a particle in uniform circular motion.
The string will break if the tension T exceeds the following value.
Tmax  =  mg
   = 
  kg
  m/s2
   =   N

As the 2.98-kg mass rotates in a horizontal circle, the tension provides the centripetal acceleration, which is specified by 
ac = v2/r.
 From Newton's second law, we have
  F = ma
 
and since
ac = 
v2
r
,
We have the following for the tension in the string.
T = 
mv2
r
 

 

 
 

Subject Science
Due By (Pacific Time) 10/20/2015 10:10 pm
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